i need your help in c++

[fritzhahaha]

---

Guys need nku inyo tabang unsaun di pg input ug arithmethic operator in a running c++ program ? dba if number or something ang e input mugmit man ta ug "cin >> " pero what if arithmetic operator na ang dpat e butang labi na and modulos % ng libog ko
heres an example na dpat mu gwas sa program:
Enter n1: 5
Enter n2: 4
Enter opt: +
-----------------
The sum is: 9

Enter n1: 5
Enter n2: 2
Enter opt: %
----------------
The remainder is: 1

note: i am using an switch statements (case) and i am using visual basic 2010 c++

[stealthghost]

c++ - Using cin.get to get an integer - Stack Overflow try daw this bro..

[dab_s_bad]

i am using visual basic 2010 c++

this is..., zero divide ^_^





'cin' can be versatile bro, all you need is the variable unsa klase. the problem of C/C++ is its very explicit in terms of its input but..., you can mitigate this with other tricks if you know.

anyways, here is a bogo/crude way of doing what you wanted ^_^
it is advised unahon nimo ang 'operator' kay mulabad imo ulo if ma-ulahi na siya ^_^
note: wala ni siya security/bounds/etc checking...

char opt = '0';
    
    cout << "Enter opt: ";
    cin >> opt;
   
   switch(opt)
   {
       case '+':
       {   
           int n1 = 0, n2 = 0;
            cout << "Enter n1: ";
            cin >> n1;
   
            cout << "Enter n2: ";
            cin >> n2;
               
            cout << "-----------------" << endl; 
            cout << "The sum is: " << n1 + n2 << endl;
       }; break;
       
       case '-':
       {     
             int n1 = 0, n2 = 0;
            cout << "Enter n1: ";
            cin >> n1;
   
            cout << "Enter n2: ";
            cin >> n2;
               
            cout << "-----------------" << endl;       
            cout << "The diference is: " << n1 - n2 << endl;
       }; break;
       
       case '*':
       {   
           int n1 = 0, n2 = 0;
            cout << "Enter n1: ";
            cin >> n1;
   
            cout << "Enter n2: ";
            cin >> n2;
               
            cout << "-----------------" << endl;         
            cout << "The product is: " << n1 * n2 << endl;
       }; break;
       
       case '/':
       {    
            float n1 = 0, n2 = 0;
            cout << "Enter n1: ";
            cin >> n1;
   
            cout << "Enter n2: ";
            cin >> n2;
               
            cout << "-----------------" << endl;        
            cout << "The quotient is: " << n1 / n2 << endl;
       }; break;
       
       case '%':
       {   
           int n1 = 0, n2 = 0;
            cout << "Enter n1: ";
            cin >> n1;
   
            cout << "Enter n2: ";
            cin >> n2;
               
            cout << "-----------------" << endl;         
            cout << "The modulo is: " << n1 % n2 << endl;
       }; break;
       
       default:
       {
           cout << "unknown" << endl;
       }       
   }

[Sarevok]

this is..., zero divide ^_^





'cin' can be versatile bro, all you need is the variable unsa klase. the problem of C/C++ is its very explicit in terms of its input but..., you can mitigate this with other tricks if you know.

anyways, here is a bogo/crude way of doing what you wanted ^_^
it is advised unahon nimo ang 'operator' kay mulabad imo ulo if ma-ulahi na siya ^_^
note: wala ni siya security/bounds/etc checking...

ato limpyohan gamay ang code

   char opt = '0';
   double n1 = 0;
   double n2 = 0;
    
   cout << "Enter n1: ";
   cin >> n1;
   
   cout << "Enter n2: ";
   cin >> n2;
    
   cout << "Enter operator: ";
   cin >> opt;
   
   cout << "-----------------" << endl; 

   switch(opt)
   {
       case '+':            
           cout << "The sum is: " << (n1 + n2) << endl;
           break;
       
       case '-':
           cout << "The diference is: " << (n1 - n2) << endl;
           break;
       
       case '*': 
           cout << "The product is: " << (n1 * n2) << endl;
           break;
       
       case '/':
           cout << "The quotient is: " << (n1 / n2) << endl;
           break;
       
       case '%': 
           cout << "The modulo is: " << (n1 % n2) << endl;
           break;
       
       default:
           cout << "unknown" << endl;
           break;      
   }

[fritzhahaha]

salamat sa idea bro nasolve nman pud nku nuon sa kdugay nku hinuktok hahaha, instructor nku gud way uso discussion lol
salamat sa ni post dri lol