Need help in JAVA plsss.. help 25problems..

[bishop__]

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Waaaa!! mga master Java man di mu..

Update nko kng unsa wla pa n solve....

11-14-17-18-19-20-22-23-24.......

sa mga nka solve salamat jud kaayo..
c lord nai bhala ninyo... kbw nmu kng kinsa mu...

ayay! gamay nalang man diay.... i suggest nga kaw nalang tingali mo solve ana total layo pa btaw deadline pod. para maka tuon pod ka bai.

java is a fun language to learn.

[bishop__]

Waaaa!! mga master Java man di mu..

Update nko kng unsa wla pa n solve....

11-14-17-18-19-20-22-23-24.......

sa mga nka solve salamat jud kaayo..
c lord nai bhala ninyo... kbw nmu kng kinsa mu...

kuhaon nato nato ning tunga nga problem:

/*
 * 19.	Write a Java class called IsPalindrome, which defines a main() method 
 * that asks the user to enter a String s, and displays whether or not s is a 
 * palindrome. A palindrome is a String which reads the same forwards and 
 * backwards, such as "laval" or "stressed desserts".
 * 
 * Code taken from my previous solution of problem #21
 *
 * @author bishop__ 
 */

import javax.swing.*;
import java.text.*;
class IsPalindrome {
	public static void main( String[] args ) {
		String s1, s2;
		int result = 0, len, index1, index2;

		s1 = JOptionPane.showInputDialog(null, "Enter a string:");
		s2 = s1;
		len = s1.length();
                // improvement: string can be cut into half to speedup comparison
       		for (index1 = 0, index2 = len - 1; index1 < len; index1++, index2--) {
			if (s1.charAt(index1) != s2.charAt(index2)) {
				result = -1;
			} 
		}			
		
		if (result == 0) {
			JOptionPane.showMessageDialog(null, "Palindrome !");  
		} else {
			JOptionPane.showMessageDialog(null, "Not Palindrome !");
		}
	}
}

[bishop__]

solutions 19 and 21 can further be enhanced by adding break; after setting result = -1;

[moz_k2]

solutions 19 and 21 can further be enhanced by adding break; after setting result = -1;

further enhancement for #19
s2 variable not necessary.
for loop condition change to index1 < index2
if condition change to s1.charAt(index1) != s1.charAt(index2)

[bishop__]

further enhancement for #19
s2 variable not necessary.
for loop condition change to index1 < index2
if condition change to s1.charAt(index1) != s1.charAt(index2)

yay! seen it too... hehehe forgot to mention thanks

[josephG]

@bishop and javapenguin
Grabiha sd nnu mo hatag answer e hungit mn sd nnu tanan..hehe

[javapenguin]

grabeha mo code javapenguin oi! with error trappings naman. hehehehe...

ako kay basic lang basta mo solve lang sa problem. saon nga self study lang man ko ani sa java then wala pod mi nag gamit java sa work. hehehehe....

You're really good bro, considering you don't use java in your work and you learned it by self studying, in my case I use it everyday.

[javapenguin]

@bishop and javapenguin
Grabiha sd nnu mo hatag answer e hungit mn sd nnu tanan..hehe

Bahala na ma tuk-an ug mag suka suka hahaha

[javapenguin]

Problem #18

/*
 * 18. Write a Java class called Reverse, which defines a main() method that asks the user to enter a String s, 
 * and displays a new String consisting of the characters in s in the reverse order. 
 * You MUST NOT use any methods defined in the String class other than charAt() and length()
 */

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

/**
 *
 * @author javapenguin
 */

public class Reverse {

    public static void main(String[] args) {
        BufferedReader input = new BufferedReader(new InputStreamReader(System.in));
        
        String s = new String();
        
        System.out.println("Please enter a string: ");
        
        try {
            s = input.readLine();
        } catch (IOException ex) {
            System.err.println(ex);
        }

        char [] chr_array = new char[s.length()];
        
        int j = 0;
        
        for (int i = s.length()-1; i >= 0;i--) {
            chr_array[j] = s.charAt(i);
            j++;
        }
        
        //new string in reverse order
        String rs = new String(chr_array);
        
        System.out.println("The reverse is > "+rs);
    }

}

[DarkCode]

CmpE pud diay ka naa mo java sauna??

naa murag kami ang ng.una sa amo batch sa COMP.E nga ng JAVA usa ra nuon ka subject ng,kumbitay jud ako grado ato... hehehe