hahaha taka-taka ra ni si benicio oh,.
172.16.1.128 /25,. reverse engineering tama si benicio,.since /25, meaning nay 25 ka 1's,.ang pasabot ana is you have a subnet mask of 255.255.255.128 (11111111.11111111.11111111.10000000),..mao ni importance sa subnet mask to determine what would be your ip adress range,., you have to determine the lowest value in your subnet mask to get the ip range, in the given problem the lowest falls to 128 on the fourth octet of subnet address.
so ang imong /25 or 255.255.255.128 nga subnetwork maka handle ug 128 host pero ang imong magamit ra is 126 ky and beginning host is reserved for your network and the last host is reserved for broadcating
so ang imong IP range ky
reserved for network host ------------ IP ranges --------------------- reserved for broadcasting
172.16.0.0 -------------------------------- 1 => 126 ----------------------------- 172.16.0.127
172.16.1.128 -------------------------------- 1 => 126 ----------------------------- 172.16.1.255
172.16.2.0 -------------------------------- 1 => 126 ----------------------------- 172.16.2.127
172.16.3.128 -------------------------------- 1 => 126 ----------------------------- 172.16.3.255
...
until
....
172.16.255.128 ----------------------------- 1 => 126 ----------------------------- 172.16.255.255
pili lang ka ana sa imo nga network range nga gamiton with your subnet mask of 255.255.255.128
,.hehehe so mao na akong natun-an sa CBT nuggets bro,.please correct me if im wrong,.hehehe,.
,.nakalimot na pod ko ana,.i was trying to review,.hehehe