need help: php error

[snowleopard]

---

<?php
$datetoday = date("m",time()) . "-" . date("d",time()) . "-"
date("Y", time());
echo $datetoday;
?>

returns,

Warning: date() [function.date]: It is not safe to rely on the system's timezone settings. You are *required* to use the date.timezone setting or the date_default_timezone_set() function. In case you used any of those methods and you are still getting this warning, you most likely misspelled the timezone identifier. We selected 'UTC' for '8.0/no DST' instead in C:\server\www\myserver.dev\public_html\date.php on line 11
11

how to solve this? napansin ko kasi blank yung timezone id sa php.ini file

*using php 5.3.5, windows 7, apache 2.2
*everything else works fine

[ChaosOrb]

add a default timezone when displaying date.

<?php
date_default_timezone_set('Asia/Manila');

$datetoday = date("m",time()) . "-" . date("d",time()) . "-"
date("Y", time());
echo $datetoday;
?>

[snowleopard]

function call lang pala yun? hehe... thanks

[ChaosOrb]

function call lang pala yun? hehe... thanks

you can also add it in php.ini file if you don't want to add default time zone in every php file you create when displaying date.

[snowleopard]

that's the prob, i tried placing a value on the date.timezone in php.ini, i still get same result, has tried to exclude date_default_timezone_set(), uncomment the date.timezone to activate it, but same result, i ended up typing a long code instead

<?php
date_default_timezone_set('Asia/Manila');
$datemonth = date("m",time());
$datetoday = date("d",time());
$yearnow = date("Y",time());
echo $datetoday, '/' ,$yearnow, '/' ,$datemonth;
?>

yung prob ko lang is what if the database is open in a different timezone, dont know what will be displayed, so i guess i have to write a different code to filter or get data on the client's side..

newbie pa kasi me sa php, 3 days running pa lang